Question

xP2=12
P= Permutation
With Solution please

Answer 1

$\textbf{Given:}$

$\mathsf{x_{P_2}=12}$

$\textbf{To find:}$

$\textsf{The value of x}$

$\textbf{Solution:}$

$\underline{\textsf{Concept:}}$

$\boxed{\mathsf{n_{P_r}=n(n-1)(n-2).\;.\;.\;.\;.\;.\;.r\;factors}}$

$\textsf{Consider,}$

$\mathsf{x_{P_2}=12}$

$\mathsf{x(x-1)=12}$

$\mathsf{x^2-x-12=0}$

$\mathsf{(x-4)(x+3)=0}$

$\implies\mathsf{x=4,-3}$

$\textsf{But, x cannot be negative}$

$\implies\boxed{\mathsf{x=4}}$

$\textbf{Answer:}$

$\textsf{The value of x is 4}$

$\textbf{Find more:}$

Find the value of 50p2​

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