xpress 12 + 5i in polar form (i.e in form of z=r cosθ +i sinθ
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z=r(CosA+i SinA) r=√12^2+5^2=13 if any complex number is z =a+bi .r=√a2+b2.
so z=13(12/13+5i/13) where tanA=5/12 z=13(CosA+SinA)
so z=13(12/13+5i/13) where tanA=5/12 z=13(CosA+SinA)
kabirumudi:
which one is the answeer"
1. 13(cos22.6 - i sin22.) 2. 13(COS22.6 + i sin22.6) 3. 13(cos23.5 - i sin23.5) 4. 13(cos23.6 - i sin23.5(
pls i can't find an ans help me
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