Xsin^3a+ycos^3a=sinacosa , xsina=ycosa prove that x^2+y^2=1
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Given xSinA – yCosA = 0
⇒ x.SinA = y CosA ........(1)
Consider
{From eq 1}
xSinA = SinACosA
x = CosA ......(2)
Substitute this value in the eq (1)
We get y = SinA
so,
x^2 + y^2 = Cos^2A + Sin^2A = 1
⇒ x.SinA = y CosA ........(1)
Consider
{From eq 1}
xSinA = SinACosA
x = CosA ......(2)
Substitute this value in the eq (1)
We get y = SinA
so,
x^2 + y^2 = Cos^2A + Sin^2A = 1
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