Question

Xsquare+2x-8

factorization

Answer 1

Answer:

x^2+2x-8

=x^2+4x-2x-8

=x(x+4)-2(x+4)

=(x-2) (x+4).

Step-by-step explanation:

hope it helps u

Answer 2

Here is your answer

$\: \: \: \: \: \: \: x {}^{2} + 2x - 8 \\ \\ = > x {}^{2} + 2x - 8 = 0\\ \\ = > x {}^{2} + 4x - 2x - 8 = 0 \\ \\ x \: (x + 4) \: \: - 2(x + 4) = 0 \\ \\ (x - 2) \: \: \: (x + 4) = 0 \\ \\ if(x - 2) = 0 \: then \\ \\ x - 2 = 0 \\ \\ x= > 2 \\ \\ if \: (x + 4) = 0 \: \: then \\ \\ x + 4 = 0 \\ \\ x = > - 4$

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