xsquare+5x+12=0 by splitting the midle term and compliting the squares
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x^2+ (4x +3x ) + 12
coz ( 4*3=12 and 4+3= 7)
taking commons
x(x+4) + 3(x+4)
taking x+4 common
(x+4)(x + 3)
coz ( 4*3=12 and 4+3= 7)
taking commons
x(x+4) + 3(x+4)
taking x+4 common
(x+4)(x + 3)
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x²+7x +12=0
x²+3x+4x+12=0
x(x+3)+4(x+3)=0
(x+3)(x+4)=0
the factors are (x+3)and (x+4)
x²+3x+4x+12=0
x(x+3)+4(x+3)=0
(x+3)(x+4)=0
the factors are (x+3)and (x+4)
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