Question

xsquare minus 26x plus133 ​

Answer 1

Given ,

${x}^{2} - 26x + 133 \\ \\ = {x}^{2} - 19x - 7x + 133 \\ \\ = x(x - 19) - 7(x - 19) \\ \\ =( x - 7)(x - 19)$

If we need to find zeroes of this polynomials , then

x - 7 = 0

=> x = 7

and

x - 19

=> x = 19