Question

xtan-¹x find the derivatives​

Answer 1

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Answer 2

Step-by-step explanation:

$i(x) = x \cdot { \tan }^{ - 1} x$

$\frac{d \cdot \: i(x)}{dx} \: = { \tan}^{ - 1} x \cdot \: d(x) \: + x \cdot \: d( { \tan}^{ - 1} x)$

$\frac{d \cdot \: i(x)}{dx} \: = { \tan }^{ - 1}x \: + \frac{x}{1 + {x}^{2} }$

You can only take derivative with respect to x here.