Question

(xvii) neg of 0.12 N solution of electrolyte will be if k = 0.024 ohm
-1 cm-1
(a) 100 ohm -1 cm² eq-1 (b) 200 ohm 1 cm² eq -
(c) 50 ohm -1 cm² eq-1 (d) None.​

Answer 1

Answer:

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Answer 2

Given info : The specific conductance of a 0.12 N solution of an electrolyte is k = 0.024 ohm¯¹cm¯¹

To find : The equivalent conductance of the solution is ...

solution : using formula,

equivalent conductance = k × 1000/N

= 0.024 × 1000/0.12

= 200 ohm¯¹cm² eq¯¹

Therefore the equivalent conductance of solution is 200 ohm¯¹cm² eq¯¹

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