Xy=160
Logx=3logy=1 for y>0x>0
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HELLO DEAR,
GIVEN:- XY = 160 & logx - 3logy = 1 {y>0,x>0}
now, logx - 3logy = 1
=> logx - log(y)³ = 1
=> log{x/(y)³} = log10
=> x/y³ = 10
=> (160/y)/y³ = 10
=> 160/y⁴ = 10
=> y⁴ = 16
=> y = 2
We need to choose the positive 4th root of 16, because the log of a negative number is undefined.y = 2 ,
x = 160/2 = 80
I HOPE IT'S HELP YOU DEAR,
THANKS
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