xy=-30, and x2+y2=61 thn find the value of (x+y)
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Answered by
3
x2 + y2 = 61 - - - - Equation (1)
xy = - 30 - - - - Equation (2)
Multiplying Equation (2) by 2 and adding to Equation (1), we get,
x2 + y2 + 2xy = 61 - 60
(x + y)2 = 1
∴ x + y = ± 1
xy = - 30 - - - - Equation (2)
Multiplying Equation (2) by 2 and adding to Equation (1), we get,
x2 + y2 + 2xy = 61 - 60
(x + y)2 = 1
∴ x + y = ± 1
Answered by
1
xy=-30
x^2+y^2=61
x^2+y^2=(x+y)^2-2xy
=(x+y)^2-2.-30=61
=(x+y)^2=61-60
=1
=x+y= 1s rootover
=1
hope it is helpful to u. ...
x^2+y^2=61
x^2+y^2=(x+y)^2-2xy
=(x+y)^2-2.-30=61
=(x+y)^2=61-60
=1
=x+y= 1s rootover
=1
hope it is helpful to u. ...
mani196:
bt answr is 1
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