xy=7,x-y=5,findx^3-y^3
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x^3-y^3=(x-y)*((x-y)^2+3xy)
=5*(5^2 +3*7)
=5*(25+21)
=5*46
=230
=5*(5^2 +3*7)
=5*(25+21)
=5*46
=230
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