Question

xy(x+y) = 1 then, 1/x³y³ - x³ - y³​

Answer 1

Answer:

x/y+y/x= -1

(x²+y²)/xy= -1

x²+y²= -xy

x²+y²+xy = 0

(x²+xy+y²) = 0

Multyplying by (x-y) on both sides we get,

(x-y)(x²+xy+y²)=(x-y)×0

By eq 1 we get,

x³-y³=0

Hence x³-y³=0

Step-by-step explanation: