Question

xy¹ =(y-x)³+y solve the difference equation​

Answer 1

Step-by-step explanation:

$xy = {(y - x)}^{3} + y \\ xy = {y}^{3} - {x}^{3} - 3 {y}^{2} x + 3y {x}^{2} + y \\ 0 = - {x}^{3} + {y}^{3} + y - 3 {y}^{2} x + 3y {x}^{2} - xy \\ 0 = - {x}^{3} + {y}^{3} + y -3xy( y - x + 1)$

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