Question

XYZ is a triangle, right angled at X, IfXY=10cm and XZ=24 cm, find YZ​ solve using pythagoras property​

Answer 1

Step-by-step explanation:

Given: XYZ is a triangle

x=90 degrees

XY=10 cm

XZ=24cm

So, using pythagoras theoram,

XY^2+XZ^2=YZ^2

(10)^2+(24)^2=YZ^2

100+576=YZ^2

676=YZ^2

sqrt 676=YZ

YZ=26 cm

Answer 2

Given :

XYZ is right angled triangle at X

• XY=10cm

• XZ=24cm

•YZ=?

To find :

•the length of YZ=?

Formula :

➡ Pythagoras theorem :

$\large\bf{(YZ)^2=(XY)^2+(XZ)^2}$

Solution :

As we know that, we use Pythagoras theorem in right angled triangle if the angle is 90 degree

• XY(Opposite side) =10cm

• XZ(adjacent side) =24cm

• YZ(hypoteuse)=?

By using Pythagoras theorem :

$\\ \implies\large\bf{(hypotenuse)^2=(opposite \: side)^2+(adjacent \: side)^2}$

$\\ \implies\large\bf{(YZ)^2=(XY)^2+(XZ)^2}$

$\\ \implies\large\bf{(YZ)^2=(10)^2+(24)^2}$

$\\ \implies\large\bf{(YZ)=\sqrt{100+576}}$

$\\ \implies\large\bf{YZ=\sqrt{676}=26cm}$

$\\ \implies\large\bf{YZ(hypotheuse)=26cm}$

➡$\boxed{\sf{ Length \:of \: YZ=26cm}}$