y’ +1/y = x
y’= dy/dx
y=?
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Answer:
v = yx which is also y = vx
And dydx = d (vx)dx = v dxdx + x dvdx (by the Product Rule)
Which can be simplified to dydx = v + x dvdx
Using y = vx and dydx = v + x dvdx we can solve the Differential Equation.
An example will show how it is all done:
Example: Solve dydx = x2 + y2xy
Can we get it in F( yx ) style?
Start with: x2 + y2xy
Separate terms: x2xy + y2xy
Simplify: xy + yx
Reciprocal of first term: ( yx )−1 + yx
Yes, we have a function of (y/x).
So let's go:
Start with: dydx = ( yx )−1 + yx
y = vx and dydx = v + x dvdx : v + x dvdx = v−1 + v
Subtract v from both sides: x dvdx = v−1
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