Question

Y-15/4y+1=0 where y is not equal to zero .( Plz apply quadratic formula)

Answer 1

Answer:

$y - \frac{15}{4y} + 1 = 0$

$4 {y}^{2} - 15 + 4y = 0$

$4 {y}^{2} + 10y - 6y - 15 = 0$

$2y(2y + 5) - 3(2y + 5) = 0$

$(2y - 3)(2y + 5) = 0$

$y= \frac{3}{2} or \: \frac{ - 5}{2}$