Question

y^2-12y+32
factories​

Answer 1

Answer:

y2-4y-8y+32

y(y-4)-8(y-4)

(y-8)(y-4)

Answer 2

Answer:

(y - 4)(y - 8)

Step-by-step explanation:

Divide 32 in 2 parts such that on adding they result the second term.

$32 = - 4 \times - 8$

$- 12y = - 4y - 8y$

${y}^{2} - 4y - 8y + 32$

Take out the common term from first 2 terms and last 2 terms and factorise.

$y(y - 4) - 8(y - 4)$

As y-4 is common it can be taken out

$(y - 4)(y - 8)$