Y^2+2√3y+3 factorise
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1
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Answered by
1
Answer:
y
2
+2
3
y+3
y2+(3+3)y+3{y}^{2} + (\sqrt{3} + \sqrt{3} )y + 3y
2
+(
3
+
3
)y+3
y2+3y+3y+3{y}^{2} + \sqrt{3}y + \sqrt{3}y + 3y
2
+
3
y+
3
y+3
y(y+3)+3(y+3)y(y + \sqrt{3} ) + \sqrt{3}(y + \sqrt{3} )y(y+
3
)+
3
(y+
3
)
(y+3)(y+3)(y + \sqrt{3} )(y + \sqrt{3} )(y+
3
)(y+
3
)
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