Math, asked by Vishal123456789001, 11 months ago

Y^2+2√3y+3 factorise

Answers

Answered by nishasingh88
1

 {y}^{2} +  2 \sqrt{3}y + 3

 {y}^{2} + (\sqrt{3} +  \sqrt{3} )y + 3

 {y}^{2} +  \sqrt{3}y +  \sqrt{3}y + 3

y(y +  \sqrt{3} ) +  \sqrt{3}(y +  \sqrt{3} )

(y +  \sqrt{3} )(y +  \sqrt{3} )

hope it helps you ⬆️⬆️⬆️⬆️⬆️

Answered by pankajroy2
1

Answer:

y

2

+2

3

y+3

y2+(3+3)y+3{y}^{2} + (\sqrt{3} + \sqrt{3} )y + 3y

2

+(

3

+

3

)y+3

y2+3y+3y+3{y}^{2} + \sqrt{3}y + \sqrt{3}y + 3y

2

+

3

y+

3

y+3

y(y+3)+3(y+3)y(y + \sqrt{3} ) + \sqrt{3}(y + \sqrt{3} )y(y+

3

)+

3

(y+

3

)

(y+3)(y+3)(y + \sqrt{3} )(y + \sqrt{3} )(y+

3

)(y+

3

)

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