Question

(y^2 +2 y+3) x (y^2 +2-3)​

Answer 1

Answer:

y

y 2

y 2 +3y−y−3=0

y 2 +3y−y−3=0⇒y(y+3)−1(y+3)=0

y 2 +3y−y−3=0⇒y(y+3)−1(y+3)=0taking (y+3)common,

y 2 +3y−y−3=0⇒y(y+3)−1(y+3)=0taking (y+3)common,⇒(y+3)(y−1)=0

y 2 +3y−y−3=0⇒y(y+3)−1(y+3)=0taking (y+3)common,⇒(y+3)(y−1)=0∴ y+3=0 OR y−1=0

y 2 +3y−y−3=0⇒y(y+3)−1(y+3)=0taking (y+3)common,⇒(y+3)(y−1)=0∴ y+3=0 OR y−1=0 y=−3 OR y=1

Answer 2

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