y^2+3/2√5y-5
plz telllllllll
Answers
Answered by
1
y²+3/2√5y-5=0
Splitting the middle term
y²+4/2√5y-√5/2y-5=0
Taking LCM
2y²+4√5y-√5y-10=0 (Denominator taken to RHS)
2y(y+2√5)-√5(y+2√5)=0
(2y-√5)(y+2√5)=0
∴y= √5/2 or -2√5
Hope you understood :)
Answered by
1
Answer:
y2+3/2 v5y-5=0
Step-by-step explanation:
Splitting the middle term
y+4/2 v5y v5/2y-5=0
Taking LCM
2y +4 v5y-v5y-10=0 (Denominator
taken to RHS)
2y(y+2 V5) V5(y +2 V5)=0
(2y- 5)(y+2V5) 0
..y= 15/2 or -275
Hope you understood :)
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