Question

Y^2+3/2 root 5y-5 find all zeros of this polynomial

Answer 1

Answer:

y= 2√5 y=-√5/2

Step-by-step explanation:

a=1. b=3/2√5 y c=-5

using quadratic equation

b±√(b²-4ac)/2a

=3/2√5 ±√((3/2√5)²-4(1)(-5))/2(1)

=3/2√5 ±√(9(5)/4+20)/2

=3/2√5±√(45+80/4)/2

=3/2√5±√(125/4)/2

=3/2√5±5/2√5/2

y=1/2(3/2√5+5√5/2) or y=1/2(3/2√5-5/2√5

y=1/2(3/2√5+5√5/2) or y=1/2(3√5-5√5/2)

=y=1/2(8√5/2) or y=1/2(-2√5 /2)

=y=1/2(4√5) or y=1/2(-√5)

y=2√5 or y = -√5/2