Math, asked by nadeemahmed111969, 7 hours ago

y^2-38y-1575=0
by completing square​

Answers

Answered by sub0703200
4

Solution for x2-38x-1575=0 equation:

x2-38x-1575=0

We add all the numbers together, and all the variables

x^2-38x-1575=0

a = 1; b = -38; c = -1575;

Δ = b2-4ac

Δ = -382-4·1·(-1575)

Δ = 7744

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x_{1}=\frac{-b-\sqrt{\Delta}}{2a}x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{7744}=88

x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-88}{2*1}=\frac{-50}{2}

=-25

x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+88}{2*1}=\frac{126}{2}

=63

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