y^2=4ax differentiate w.r.t x
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This can also be written as
y = 2√ax
then differentiating with respect to x.....
dy/dx = 2a[d(√x) / dx
= 2a * 1 / 2√x ( since differentiation of √x is 1 / √x)
rationalizing the final equation gives you...
a√x / x....
Hope This Helps...
PLEASE LET ME KNOW IN THE COMMENTS IF I AM WRONG.
y = 2√ax
then differentiating with respect to x.....
dy/dx = 2a[d(√x) / dx
= 2a * 1 / 2√x ( since differentiation of √x is 1 / √x)
rationalizing the final equation gives you...
a√x / x....
Hope This Helps...
PLEASE LET ME KNOW IN THE COMMENTS IF I AM WRONG.
dolly45:
2y.dy/dx=4a,then dy/dx=4a/2y, then dy/dx=2a/y.is the correct answer.
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