Two angles of a triangle are equal and the third angle is greater than each of the those angle by 30 degree determine all the angle of the triangle
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Let all three angles of triangles are x, y, z
x = y given (1)
z = x + 30 or z = y + 30 also given (2)
sum of all the angles of triangle is equal to 180°,
hence,
x + y + z = 180° (from triangle property sum of angles of triangle are straight angle(180°))
using equation (1) & (2) in (3), we get
x + x + x + 30 = 180° (from eq. 1 & 2)
3x + 30 = 180°
3x = 180-30
x = 150÷3
x = 50°
hence,
z = 50 + 30= 80°
x = y given (1)
z = x + 30 or z = y + 30 also given (2)
sum of all the angles of triangle is equal to 180°,
hence,
x + y + z = 180° (from triangle property sum of angles of triangle are straight angle(180°))
using equation (1) & (2) in (3), we get
x + x + x + 30 = 180° (from eq. 1 & 2)
3x + 30 = 180°
3x = 180-30
x = 150÷3
x = 50°
hence,
z = 50 + 30= 80°
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