Question

y^2-5/3 y =-1/3 solve in quadratic formula

Answer 1

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Answer 2

Answer:

y^2-5/3y= -1/3

3y^2-5y/3 =-1/3

3y^2-5y=-1

3y^2-5y+1=0

Now,by Shridharacharya formula,we have

a=3,,b=5 and c=1 so,

D=(b^2-4ac)

=(5^2-4.3.1)

=(25-12)=13..

y=-b(+-)√d/2a. (since,+-means +or-).

y=-5(+-)√13/2.3

y=-5(+-)√13/6

Now,there is two answer in + and -..

then,y=-5+√13/6 and y=-5-√13/6...

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