Question

(y^2-6y+9)(y^2-36)=with steps

Answer 1

$( {y}^{2} - 6y + 9)(y {}^{2} - 36) = 0 \\ (y - 3) {}^{2} (y + 6)(y - 6) = 0 \\ if \\ y - 3 = 0 \\ y = 3 \\ if \: y + 6 = 0 \\ y = - 6 \\ \\ if \\ (y -6) = 0 \\ y = 6$
y=6,-6,3