(y ²+ 7y + 10) ÷ (y + 5)
Answers
Answer:
(y2 + 7y + 10) ÷ (y + 5)
Let us facterise the (y2 + 7y + 10)
By splitting the middle term we need to find the two numbers such that, there
Sum = 7
Product = 10
Let us consider the two numbers 2 and five, so
Sum = 2 + 5 = 7
Product = 2 × 5 = 10
So, we can write
y2 + 7y + 10 = y2 + 2y + 5y + 10
y2 + 2y + 5y + 10 = y (y + 2) + 5(y + 2)
y (y + 2) + 5(y + 2) = (y + 2)(y + 5)
y2 + 7y + 10 = (y + 2)(y + 5)
⇒
(
y
2
+
7
y
+
10
)
(
y
+
5
)
(y2+7y+10)(y+5)
⇒
(
y
+
2
)
(
y
+
5
)
(
y
+
5
)
(y+2)(y+5)(y+5)
⇒
(
y
+
2
)
×
(
y
+
5
)
(
y
+
5
)
(y+2)×(y+5)(y+5)
⇒ (y + 2)
(y2 + 7y + 10) ÷ (y + 5) = (y + 2)
Step-by-step explanation:
To solve :
Solution :
- To divide the given algebraic equations we first factorize numerator by splitting the middle term.
- factors of
- Taking common
- Now , dividing given equation by substituting above factors of numerator we get,
Hence , is the correct answer.