Question

y = 2^x + cos 3x find dy/dx

Answer 1

$y = {2}^{x} + \cos(3x) \\ let \: m = {2}^{x} \\ take \: log \: \\ log(m) = x log(2) \\ (1 \div m)(dm \div dx) = log2 \\ dm \div dx = mlog2 \\ dm \div dx = {2}^{x} log_{}(2) \\ y = m + \cos(3x) \\ (dy \div dx) = (dm \div dx) - 3 \sin(3x) \\ (dy \div dx) = {2}^{x} log(2) - 3 \sin(3x)$
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