Math, asked by rasika3, 1 year ago

y = 2^x + cos 3x find dy/dx

Answers

Answered by saurabhsemalti
1

y =  {2}^{x}  +  \cos(3x)  \\ let \: m =  {2}^{x}  \\ take \: log \: \\  log(m)  = x log(2)  \\ (1 \div m)(dm \div dx) = log2 \\ dm \div dx = mlog2 \\ dm \div dx =  {2}^{x}  log_{}(2)  \\ y = m +  \cos(3x)  \\ (dy \div dx) = (dm \div dx) - 3 \sin(3x)  \\ (dy \div dx) =  {2}^{x}  log(2)  - 3 \sin(3x)
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