Math, asked by princekaushik98793, 8 days ago

y^2-y-90 divided by y-10 factorisation method​

Answers

Answered by krishpmlak
0

Answer:

Step-by-step explanation:

Let p (y) = y² - y - 90 and ( y - 10 )is a factor of p (y ),

Then y - 10 = 0 ⇒ y = 10.

Now substituting " y = 10 " in p (y ),we get

p ( 10 ) = ( 10 )² - 10 - 90

= 100 - 100 ( ∵ adding : - 10 - 90 = - 100 )

= 0.

Hence, ( y - 10 ) is a factor of p(y) = y² - y - 90 .

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