y-2x=7 and 4y+x=1 solve by substitution
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Answered by
3
y - 2x=7
y=2x + 7
put this in 4y + x=1
=4(2x+7) + x=1
=8x+ 28+x=1
9x= -27
x = -3
so y=2x+7
y=2(-3)+7
y=1.
y=2x + 7
put this in 4y + x=1
=4(2x+7) + x=1
=8x+ 28+x=1
9x= -27
x = -3
so y=2x+7
y=2(-3)+7
y=1.
Answered by
9
i) y-2x = 7. And. ii) 4y+x = 1
i) y=7+2x
Now replacing y by its value in (ii)
4(7+2x)+x = 1
28+8x+x = 1
28+9x = 1
9x = 1-28
9x = -27
x =
Now y will be ;
4y + (-3) = 1
4y-3=1
4y=4
i) y=7+2x
Now replacing y by its value in (ii)
4(7+2x)+x = 1
28+8x+x = 1
28+9x = 1
9x = 1-28
9x = -27
x =
Now y will be ;
4y + (-3) = 1
4y-3=1
4y=4
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