Question

Y^3+2xy=5 find Dy/dx ?

Answer 1

Answer:-2y/(3y²+2x)

Step-by-step explanation:

y³+2xy=5.......y³+2xy-5 = 0

0 = dy/dx 3y² + [(2x × dy/dx) + (y ×2)] -0

0 = 3y²dy/dx + 2xdy/dx +2y

Factorise out the dy/dx

0 = dy/dx(3y²+ 2x) +2y

-2y = dy/dx(3y²+2x)

-2y/(3y²+2x) = dy/dx