y^3+3y^+3y+1 , find factors
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Answered by
1
☑Here is your answer ⤵
▶3y^3 + 3y^2 + y + 1 = 0
▶3y^2(y + 1) + 1(y + 1) = 0
▶(y + 1)(3y^2 + 1) = 0
✨y = -1. And. y = +- 1/3
❇Hope it helps you....
⚫Pl mark it the brainliest answer.....
9jenish:
thank you bro
bro you did one mistake in third term it is 3y not only y plz answer me
Answered by
1
Answer: (y-1)³
Step-by-step explanation:
y³+3y²+3y+1=(y-1)³
plz explain the steps
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