Question

y – 3)/4 + (y – 1)/5 – (y – 2)/3 = 1
(3x – 2)/3 + (2x + 3)/3 = (x + 7)/6
(8y – 5)/(7y + 1) = -4/5
(5 – 7y)/(2 + 4y) = -8/7. Solve these linear equations..​

Answer 1

Answer:

(

4

3(y−5)

)−4y=3−(

2

(y−3)

)

3(y−5)−16y=12−2(y−3)

3y−15−16y=12−2y+6

3y−16y+2y=12+6+15

−11y=33

∴y=−3

Step-by-step explanation:

2.

(3x-2)/3+(2x+3)/3=x+7/6

We move all terms to the left:

(3x-2)/3+(2x+3)/3-(x+7/6)=0

We add all the numbers together, and all the variables

(3x-2)/3+(2x+3)/3-(+x+7/6)=0

We get rid of parentheses

(3x-2)/3+(2x+3)/3-x-7/6=0

We calculate fractions

There is no solution for this equation