Math, asked by renukaadv2001, 1 year ago

(y-3)/5 + (y-4)/7 = 6 - ((2y-2)/35)

Answers

Answered by shikha423
0

Step-by-step explanation:

(y-3)/5 +(y-4)/7+(2y-2) =6

((7y-21) + (5y-20) + (2y-2))/35 = 6

7y- 21 + 5y-20 + 2y - 2/ 35 =6

14y -43 /35 = 6

14y -43 = 6×35

14y = 210 + 43

14y = 253

y = 18.07143

Answered by deepali41
1

 \frac{y - 3}{5}  +  \frac{y - 4}{7}  = 6 -  \frac{(2y - 2)}{35}

 \frac{7y - 21 + 5y - 20}{35}  = \frac{210 - 2y + 2}{35}

7y-21+5y-20 = 210-2y+2

12y-41= 212-2y

12y+2y = 212+41

14y = 253

y =  \frac{253}{14}

y = 18.071.

hope this will help u .........

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