Math, asked by YAMINITHAKUR08, 7 hours ago

(y^3+7)(y^3-8) is equal to

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Answered by gayathriharish22

0

Answer:

please refer the attachment for the answer

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Answered by saaditya258

0

Answer:

Y^3×Y^3-Y^3×8+Y^3×7-8×7

= Y^6-8Y^3+7Y^3-56

=Y^6-Y^3-56

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