Question

Y^3--8 by Y--2 divide polynomial by binomial ​

Answer 1

Solution :

We know that,

a³ - b³ = (a - b) (a² + ab + b²)

∴ (y³ - 8) / (y - 2)

= {(y³) - (2)³} / (y - 2)

= {(y - 2) (y² + 2y + 4)} / (y - 2)

= y² + 2y + 4 ,

which is the required quotient.