Question

Y=(3x²+7)/(2x³+x) Then dy/dx??​

Answer 1

y = (3x^2 +7) / (2x^3 + x)

dy/dx = d/dx (3x^2 +7)/(2x^3+×)

=(2x^3+x)d/dx(3x^2+7)-(3x^2+7)d/dx

(2x^3+x)

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(2x^3+x)^2

= (2x^3+x)(3×2 x) - (3x^2+7)( 2×3 x^2 + 1)

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( 2x^3 + x)^2

= 6x ( 2x^3 + x) - ( 3x^2 +7)(6x^2 +1)

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(2x^3 + x )^2

= 12 x^4 + 6x^2 - (18x^4 + 3x^2 +42x^2 +7)

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( 2x^3 +x)^2

= ( - 6x^4 - 39x^2 -7)/ (2x^3 + x)^2