Question

y^4+y^2 by y^2-2 division of algebraic expression​

Answer 1

Answer:

Quotient =

${y}^{2} + 3$

Residue = 6

Step-by-step explanation:

${y}^{4} + {y}^{2} \\ \\ = {y}^{4} - 2 {y}^{2} + 2 {y}^{2} + {y}^{2} \\ \\ = {y}^{2} ( {y}^{2} - 2) + 3 {y}^{2} - 6 + 6\\ \\ = {y}^{2} ( {y}^{2} - 2) + 3( {y}^{2} - 2) + 6 \\ \\ = ({y}^{2} - 2)( {y}^{2} + 3) + 6$