y"+4y=∆(t-π)-∆(t-π) if y(0)=1,y'(0)=1
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s-1. + 1 s2 + 1 s + 9s + 15 s2 + 2s - 3 . c. y// - 4y = { sint. 0 <t<π,. -sint t > π. ; y(0) ... where T is the period of f ( which in this case is π), and fT is the function over one ...
Missing: ∆(
this is the answer pls mark as brainlist
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