Question

IE 1 and IE2 of metal M is 600kJ/mol and 1600kJ/mol. If 1000kJ of energy is supplied to one mole of vapour of M, then the resulting mixture mole percentage of M+2 is 5X find X.
(IE =ionisation energy)

Answer 1

IE 1 and IE2 of metal M is 600kJ/mol and 1600kJ/mol. If 1000kJ of energy is supplied to one mole of vapour of M, then the resulting mixture mole percentage of M+2 is 5X

X is carbon monoxide

Answer 2

Answer:

X=5

Explanation:

IE1=600 kj/mol IE2=1600 kj/mol

unconsumed energy in IE1

1000-600=400

M+2=400/1000×100

25=5x

X=5