y"-6y'-7y=0 solve this question
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the above equation corresponds to the quadratic equation
ax² +bx +c= 0
then,
y² -6y -7 = 0
(y -7)(y + 1) = 0
then,
y= 7 or. y= -1
ax² +bx +c= 0
then,
y² -6y -7 = 0
(y -7)(y + 1) = 0
then,
y= 7 or. y= -1
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