y/7=3, Write the following in the form of ax+by+c=0 and find the values of a, b and c.
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Answered by
4
y=21
y-21=0
by comparing to form ax+by+c=0
a=0
b=1
c=-21
y-21=0
by comparing to form ax+by+c=0
a=0
b=1
c=-21
Answered by
8
Given linear equation y/7 = 3
Multiply both sides with 7 ,
we get
=> y = 21
=> y - 21 = 0
=> 0×x + 1×y + ( -21 ) = 0
Compare this with ax+by+c=0,
we get
a = 0 , b = 1 , c = -21
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