Math, asked by Anonymous, 19 hours ago

(y-8)×(3y-4)=?
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please explain me​

Answers

Answered by shivangivats799
1

Answer:

3y²-28y+32

Step-by-step explanation:

y(3y-4) x -8(3y-4)

3y²-4y -24y + 32

3y²-28y+32

This is the solution for your question!

Answered by masura8080
0

From the given question the correct answer is:

(y-8)×(3y-4)=3y²-28y+32

Given:

(y-8)×(3y-4)

To find:

(y-8)×(3y-4)=?

Solution:

we have to simplify the (y-8)×(3y-4)

so first we will multiply the first bracket to the secomd

so, we get

(y-8)×(3y-4)

=y(3y-4)-8(3y-4)

=3y²-4y-24y+32

=3y²-28y+32

This is in the form quadratic equation of ax²-bx+c

hence,  (y-8)×(3y-4)=3y²-28y+32

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