(y-8)×(3y-4)=?
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please explain me
Answers
Answered by
1
Answer:
3y²-28y+32
Step-by-step explanation:
y(3y-4) x -8(3y-4)
3y²-4y -24y + 32
3y²-28y+32
This is the solution for your question!
Answered by
0
From the given question the correct answer is:
(y-8)×(3y-4)=3y²-28y+32
Given:
(y-8)×(3y-4)
To find:
(y-8)×(3y-4)=?
Solution:
we have to simplify the (y-8)×(3y-4)
so first we will multiply the first bracket to the secomd
so, we get
(y-8)×(3y-4)
=y(3y-4)-8(3y-4)
=3y²-4y-24y+32
=3y²-28y+32
This is in the form quadratic equation of ax²-bx+c
hence, (y-8)×(3y-4)=3y²-28y+32
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