Question

y= (8x^3+7sinx)^7 differentiation question​

Answer 1

$y = ( {8 {x}^{3} + 7sinx})^{7} \\ \frac{dy}{dx} = 7(8 {x}^{3} + 7sinx) ^{6} \frac{d}{dx} (8 {x}^{3} + 7sinx) \\ = 7( {8 {x}^{3} + 7sinx})^{6} (24 {x}^{2} + 7cosx)$