y= asinA, x=acosA is the euation of a circle or not if yes then why?,
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see the general equation of the circle can be (x-h)^2+(y-k)^2=a^2
where (h, k) are the coordinates of the center and a is the radius
so if we square the values you have given oh x and y then we get
x^2+y^2=(asinA)^2+(acosA)^2
x^2+y^2=a^2 (sinA^2+cosA^2)
and as we know sinA^2+cosA^2 will be 1 then we get finally
x^2+y^2=a^2
which we can say is a eq of circle with center (0, 0) and radius, a
where (h, k) are the coordinates of the center and a is the radius
so if we square the values you have given oh x and y then we get
x^2+y^2=(asinA)^2+(acosA)^2
x^2+y^2=a^2 (sinA^2+cosA^2)
and as we know sinA^2+cosA^2 will be 1 then we get finally
x^2+y^2=a^2
which we can say is a eq of circle with center (0, 0) and radius, a
tarun0001:
great bro u r 100% right
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