Question

y=asinmx + bcosmx then d^y/dx^2​

Answer 1

Step-by-step explanation:

dy/dx=a(cosmx)(m) + b(-sinmx)m

dy/dx=amcosmx-bmsinmx

d^2y/dx^2=am(-sinmx)m-bm(cosmx)m

= -m^2(asinmx+bcosmx)