Question

y= ax +b/cx+d 2y'y'''=3(y")^2 , when a+d = 0

Answer 1

y' = (ax + b) * (-1) * (cx + d)^- 2 * (c) + (cx + d)^-1 * (a) = (cx + d)^-1 * [a ... 3( y")^2 = 3[4c^2(ad - bc)^2(cx + d)^-6] = 12c^2( ad - bc)^2(cx + d)^-6 ... 0 ...