Math, asked by sudiptapramanik252, 4 days ago

y = cos 3x sin 4x find second derivative​

Answers

Answered by jatothb
1

Answer:

Answer

y"=144 cos3x sin4x

y'=(-3sin3x)(4cos4x)

y'= -12 sin3x cos4x

y"=(-12)(3cos3x)(-4sin4x)

y"=144 cos3x sin4x

y"=144 y

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