Question

y = e^x - 3 find its derivatives ?​

Answer 1

Answer:e^x

Since 3 is a constant its derivative is zero and e^x derivative is always e^x

Step-by-step explanation:

Answer 2

Answer:

$\large\boxed{\sf{{e}^{x}}}$

Step-by-step explanation:

Given a function such that,

$y = {e}^{x} - 3$

To find it's derivative.

Differentiatiating both the sides wrt x, we get,

$= > \dfrac{dy}{dx} = \dfrac{d}{dx} ( {e}^{x} - 3) \\ \\ = > \dfrac{dy}{dx} = \dfrac{d}{dx} {e}^{x} - \dfrac{d}{dx} (3)$

But, we know that,

• $\dfrac{d}{dx} {e}^{x} = {e}^{x}$
• $\dfrac{d}{dx} c = 0$

Where, C is any constant .

Therefore, we will get,

$= > \dfrac{dy}{dx} = {e}^{x} -0 \\ \\ = > \dfrac{dy}{dx} = {e}^{x}$

Hence, the required derivative is $\bold{{e}^{x}}$