Question

y=log(log x); then dy÷dx=?​

Answer 1

Question : y = log ( log x ) ; then dy ÷ dx = ?​

Answer:

Step-by-step explanation:

y = log ( log x )  ( # = log x where x = ( log x) # )

=> dy / dx

=> d/dx( log ( log x ) )

Since derivative of log x is 1/x

=> 1 / log x.d/dx(log x)

=> 1/log x . 1/x

=> 1/(x.log x )

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